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6-5/6x=7/^-4
We move all terms to the left:
6-5/6x-(7/^-4)=0
Domain of the equation: 6x!=0We get rid of parentheses
x!=0/6
x!=0
x∈R
-5/6x+6+4-7/^=0
We calculate fractions
()/6x^2+(-42x)/6x^2+6+4=0
We add all the numbers together, and all the variables
()/6x^2+(-42x)/6x^2+10=0
We multiply all the terms by the denominator
(-42x)+10*6x^2+()=0
We add all the numbers together, and all the variables
(-42x)+10*6x^2=0
Wy multiply elements
60x^2+(-42x)=0
We get rid of parentheses
60x^2-42x=0
a = 60; b = -42; c = 0;
Δ = b2-4ac
Δ = -422-4·60·0
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-42}{2*60}=\frac{0}{120} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+42}{2*60}=\frac{84}{120} =7/10 $
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